4x-8/x^2-4x+4

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Solution for 4x-8/x^2-4x+4 equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

4*x-(4*x)-(8/(x^2))+4 = 0

4*x-4*x-8*x^-2+4 = 0

-8*x^-2 = -4 // : -8

x^-2 = 1/2

-2 < 0

1/(x^2) = 1/2 // * x^2

1 = 1/2*x^2 // : 1/2

2 = x^2

x^2 = 2 // ^ 1/2

abs(x) = 2^(1/2)

x = 2^(1/2) or x = -2^(1/2)

x in { 2^(1/2), -2^(1/2) }

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